3. Enter and analyze two-way table...

통계 > 분할표 > 이원표 입력 및 분석하기...

Statistics > Contingency tables > Enter and analyze two-way table...

Linux 사례 (MX 21)

'통계 > 분할표 > 이원표 입력 및 분석하기...' 메뉴 기능을 선택하면 하위 창이 등장한다. '변수 이름', '행과 열의 수', '사례 수' 등을 입력할 수 있다. 아래의 내용은 'chisq.test' 함수 도움말 문서에 나오는 사례를 입력한다. 아래의 입력 스크립트를 참조 할 수 있다.

Linux 사례 (MX 21)

Linux 사례(MX 21)

.Table <- matrix(c(762,327,468,484,239,477), 2, 3, byrow=TRUE)
dimnames(.Table) <- list("Gender"=c("Female", "Male"), "Party"=c("Democrats", "Independent", 
  "Republican"))
.Table  # Counts
.Test <- chisq.test(.Table, correct=FALSE)
.Test
.Test$expected # Expected Counts

Linux 사례 (MX 21)

---

?chisq.test  # stats 패키지의  chisq.test 도움말 보기

## From Agresti(2007) p.39
M <- as.table(rbind(c(762, 327, 468), c(484, 239, 477)))
dimnames(M) <- list(gender = c("F", "M"),
                    party = c("Democrat","Independent", "Republican"))
(Xsq <- chisq.test(M))  # Prints test summary
Xsq$observed   # observed counts (same as M)
Xsq$expected   # expected counts under the null
Xsq$residuals  # Pearson residuals
Xsq$stdres     # standardized residuals


## Effect of simulating p-values
x <- matrix(c(12, 5, 7, 7), ncol = 2)
chisq.test(x)$p.value           # 0.4233
chisq.test(x, simulate.p.value = TRUE, B = 10000)$p.value
                                # around 0.29!

## Testing for population probabilities
## Case A. Tabulated data
x <- c(A = 20, B = 15, C = 25)
chisq.test(x)
chisq.test(as.table(x))             # the same
x <- c(89,37,30,28,2)
p <- c(40,20,20,15,5)
try(
chisq.test(x, p = p)                # gives an error
)
chisq.test(x, p = p, rescale.p = TRUE)
                                # works
p <- c(0.40,0.20,0.20,0.19,0.01)
                                # Expected count in category 5
                                # is 1.86 < 5 ==> chi square approx.
chisq.test(x, p = p)            #               maybe doubtful, but is ok!
chisq.test(x, p = p, simulate.p.value = TRUE)

## Case B. Raw data
x <- trunc(5 * runif(100))
chisq.test(table(x))            # NOT 'chisq.test(x)'!